36x^2+6x-16=0

Solution for 36x^2+6x-16=0 equation:

36x^2+6x-16=0

a = 36; b = 6; c = -16;
Δ = b2-4ac
Δ = 62-4·36·(-16)
Δ = 2340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2340}=\sqrt{36*65}=\sqrt{36}*\sqrt{65}=6\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{65}}{2*36}=\frac{-6-6\sqrt{65}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{65}}{2*36}=\frac{-6+6\sqrt{65}}{72}
$